0=1-102p+102p^2

Solution for 0=1-102p+102p^2 equation:

0=1-102p+102p^2

We move all terms to the left:

0-(1-102p+102p^2)=0

We add all the numbers together, and all the variables

-(1-102p+102p^2)=0

We get rid of parentheses

-102p^2+102p-1=0

a = -102; b = 102; c = -1;
Δ = b2-4ac
Δ = 1022-4·(-102)·(-1)
Δ = 9996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9996}=\sqrt{196*51}=\sqrt{196}*\sqrt{51}=14\sqrt{51}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(102)-14\sqrt{51}}{2*-102}=\frac{-102-14\sqrt{51}}{-204}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(102)+14\sqrt{51}}{2*-102}=\frac{-102+14\sqrt{51}}{-204}
$